0=164-12x-16x^2

Solution for 0=164-12x-16x^2 equation:

0=164-12x-16x^2

We move all terms to the left:

0-(164-12x-16x^2)=0

We add all the numbers together, and all the variables

-(164-12x-16x^2)=0

We get rid of parentheses

16x^2+12x-164=0

a = 16; b = 12; c = -164;
Δ = b2-4ac
Δ = 122-4·16·(-164)
Δ = 10640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10640}=\sqrt{16*665}=\sqrt{16}*\sqrt{665}=4\sqrt{665}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{665}}{2*16}=\frac{-12-4\sqrt{665}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{665}}{2*16}=\frac{-12+4\sqrt{665}}{32}
$